2016 AMC 10A Problem 2

Attempt Problem 2 of the 2016 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10A solutions, or check the answer key.

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2.

For what value of xx does 10x1002x=10005?10^{x} \cdot 100^{2x}=1000^{5}?

11

22

33

44

55

Answer: C
Concepts:exponent
Difficulty rating: 770
Solution:

Rewrite all bases as powers of 1010: 10x1002x=10x(102)2x=105x,\small 10^x\cdot100^{2x}=10^x\cdot(10^2)^{2x}=10^{5x}, and 10005=(103)5=1015.1000^5=(10^3)^5=10^{15}.

Therefore 5x=155x=15, so x=3x=3.

Thus, the correct answer is C.

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