2014 AMC 10A Problem 1

Attempt Problem 1 of the 2014 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

What is the value of the following expression?
10⋅(12+15+110)−1 10\cdot\left(\dfrac{1}{2}+\dfrac{1}{5}+\dfrac{1}{10}\right)^{-1}
33
88
252\dfrac{25}{2}
1703\dfrac{170}{3}
170170
Answer: C
Concepts:fractionorder of operations
Small hint:
Add the fractions inside the parentheses first
Big hint:
Take the reciprocal before multiplying by 1010
Solution:
We get that 12+15+110=510+210+110=45.\begin{aligned} &\dfrac{1}{2} + \dfrac{1}{5} + \dfrac{1}{10} \\ &= \dfrac{5}{10} + \dfrac{2}{10} + \dfrac{1}{10} \\&= \dfrac{4}{5}. \end{aligned}
Then (45)−1=54\left(\dfrac{4}{5}\right)^{-1} = \dfrac{5}{4} and then finally, 10⋅54=252.10 \cdot \dfrac{5}{4} = \dfrac{25}{2}.
Thus, C is the correct answer.
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