2010 AMC 10B Problem 9

Attempt Problem 9 of the 2010 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

Lucky Larry’s teacher asked him to substitute numbers for a,a, b,b, c,c, d,d, and ee in the expression a−(b−(c−(d+e)))a-(b-(c-(d+e))) and evaluate the result. Larry ignored the parentheses but added and subtracted correctly and obtained the correct result by coincidence. The numbers Larry substituted for a,a, b,b, c,c, and dd were 1,1, 2,2, 3,3, and 4,4, respectively. What number did Larry substitute for e?e?
−5-5
−3-3
00
33
55
Answer: D
Concepts:order of operationslinear equation
Small hint:
Compare Larry’s ignored-parentheses value to the correct value
Big hint:
Correctly evaluated, the expression is −2−e-2-e
Solution:
Ignoring the parentheses, Larry would get 1−2−3−4+e=e−8. 1 - 2 - 3 - 4 + e = e - 8.
Evaluating with the parentheses, one would get 1−(2−(3−(4+e)))=1−(2−(−1−e))=1−(3+e)=−2−e.\begin{aligned} &1 - (2 -(3 - (4 + e)))\\ & = 1 - (2 - (-1 - e))\\ &= 1 - (3 + e) \\ &=-2 - e.\end{aligned}
Both of these values are the same, so e−8=−2−e e - 8 = -2 - e e=3. e = 3.
Thus, D is the correct answer.
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