2025 AIME II Problem 1

Attempt Problem 1 of the 2025 AIME II below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AIME II solutions, or check the answer key.

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1.

Six points A,A, B,B, C,C, D,D, E,E, and FF lie in a straight line in that order. Suppose that GG is a point not on the line and that AC=26,AC = 26, BD=22,BD = 22, CE=31,CE = 31, DF=33,DF = 33, AF=73,AF = 73, CG=40,CG = 40, and DG=30.DG = 30. Find the area of BGE.\triangle BGE.

Answer: 468
Concepts:coordinate geometrydistance formulatriangle area
Difficulty rating: 2010
Solution:

Place the line on a number line with A=0.A = 0. Then C=26,C = 26, E=26+31=57,E = 26 + 31 = 57, F=73,F = 73, D=7333=40,D = 73 - 33 = 40, and B=4022=18.B = 40 - 22 = 18.

Write G=(x,y).G = (x, y). From CG=40CG = 40 and DG=30,DG = 30, (x26)2+y2=1600,(x - 26)^2 + y^2 = 1600, (x40)2+y2=900.(x - 40)^2 + y^2 = 900. Subtracting gives 14(2x66)=700,14(2x - 66) = 700, so x=58,x = 58, and then y2=1600322=576,y^2 = 1600 - 32^2 = 576, so GG is at height 2424 above the line.

Since BB and EE both lie on the line, BE=5718=39BE = 57 - 18 = 39 is a base with height 24,24, so the area is 123924=468.\frac{1}{2} \cdot 39 \cdot 24 = 468.

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