2008 AMC 8 第 24 题

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24.

编号为 111010 的十块牌面朝下放着。随机翻开一块牌,并掷一个骰子。牌上的数与骰子点数的乘积是平方数的概率是多少?

Ten tiles numbered 11 through 1010 are turned face down. One tile is turned up at random, and a die is rolled. What is the probability that the product of the numbers on the tile and the die will be a square?

 110\ \dfrac{1}{10}

 16\ \dfrac{1}{6}

 1160\ \dfrac{11}{60}

 15\ \dfrac{1}{5}

 730\ \dfrac{7}{30}

答案:C
知识点:基本概率完全平方数分类讨论
难度评级:1630
解答:

如果骰子点数为 11,牌可以是 1,4,91,4,9,有 33 种组合。

如果骰子点数为 22,牌可以是 2,82,8,有 22 种组合。

如果骰子点数为 33,牌可以是 33,有 11 种组合。

如果骰子点数为 44,牌可以是 1,4,91,4,9,有 33 种组合。

如果骰子点数为 55,牌可以是 55,有 11 种组合。

如果骰子点数为 66,牌可以是 66,有 11 种组合。

组合总数为 共有 6060 个等可能组合,所以概率是 1160\dfrac{11}{60} 3+2+1+3+1+1=11.3+2+1+3+1+1=11.

所以正确答案是 C

If the rolled number was 1,1, then the tile can be 1,4,9,1,4,9, yielding 33 combinations.

If the rolled number was 2,2, then the tile can be 2,8,2,8, yielding 22 combinations.

If the rolled number was 3,3, then the tile can be 3,3, yielding 11 combination.

If the rolled number was 4,4, then the tile can be 1,4,9,1,4,9, yielding 33 combinations.

If the rolled number was 5,5, then the tile can be 5,5, yielding 11 combination.

If the rolled number was 6,6, then the tile can be 6,6, yielding 11 combination.

The total number of combinations is 3+2+1+3+1+1=11.3+2+1+3+1+1=11. There are 6060 combinations each with equal likelihood, so the probability is 1160.\dfrac{11}{60} .

Thus, the answer is C .

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