Question

两个 $600$ mL 的水壶中装有橙汁。一个水壶装了 $\frac 13$ 满，另一个装了 $\frac 25$ 满。向每个水壶中加水直到装满，然后把两个水壶都倒入一个大容器。大容器中混合液的橙汁占几分之几？

Two $600$ mL pitchers contain orange juice. One pitcher is $\frac 13$ full and the other pitcher is $\frac 25$ full. Water is added to fill each pitcher completely, then both pitchers are poured into one large container. What fraction of the mixture in the large container is orange juice?

$\dfrac{1}{8}$

$\dfrac{3}{16}$

$\dfrac{11}{30}$

$\dfrac{11}{19}$

$\dfrac{11}{15}$

答案：C

知识点：混合问题分数

难度评级：1160

解答：

第一个水壶含有 $600 \cdot \dfrac{1}{3} = 200$ mL 橙汁。第二个含有 $600 \cdot \dfrac{2}{5} = 240$ mL。

大容器中共有 $200 + 240 = 440$ mL 橙汁。混合液总量为 $2 \cdot 600 = 1200$ mL。

因此橙汁所占比例为 $\dfrac{440}{1200} = \dfrac{11}{30}$ 。

所以正确答案是 C。

The first pitcher contains $600 \cdot \dfrac{1}{3} = 200$ mL of orange juice. The second one has $600 \cdot \dfrac{2}{5} = 240$ mL.

The large container then has $200 + 240 = 440$ mL of orange juice. The total amount of mixture is $2 \cdot 600 = 1200$ mL.

Then the fraction of orange juice is $\dfrac{440}{1200} = \dfrac{11}{30}.$

Thus, C is the correct answer.

2004 AMC 8 第 16 题

答案：C

难度评级：1160

解答：

其他年份的第 16 题