2004 AMC 8 Problem 13

Below is the professionally curated solution for Problem 13 of the 2004 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 8 solutions, or check the answer key.

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Concepts:logical deductioncasework

Difficulty rating: 1190

13.

Amy, Bill and Celine are friends with different ages. Exactly one of the following statements is true.

I. Bill is the oldest.

II. Amy is not the oldest.

III. Celine is not the youngest.

Rank the friends from the oldest to youngest.

Bill, Amy, Celine\text{Bill, Amy, Celine}

Amy, Bill, Celine\text{Amy, Bill, Celine}

Celine, Amy, Bill\text{Celine, Amy, Bill}

Celine, Bill, Amy\text{Celine, Bill, Amy}

Amy, Celine, Bill\text{Amy, Celine, Bill}

Solution:

If Bill were oldest, then statements I and II would both be true, so Bill is not oldest.

If Celine were oldest, then statements II and III would both be true, so Celine is not oldest.

Therefore Amy is oldest. Statements I and II are false, so statement III must be the single true statement. Thus Celine is not youngest, leaving Bill youngest.

The order is Amy, Celine, Bill.

Thus, E is the correct answer.

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