1993 AMC 8 Problem 13

Below is the professionally curated solution for Problem 13 of the 1993 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

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Concepts:area decomposition

Difficulty rating: 960

13.

The word "HELP" in block letters is painted as a shaded region with strokes 11 unit wide on a 55 by 1515 rectangular sign. Each letter is 33 units wide with a 11-unit gap between letters, as shown. The area of the unshaded portion of the sign, in square units, is

3030

3232

3434

3636

3838

Solution:

The full sign has area 5×15=755 \times 15 = 75 square units. Counting the shaded unit squares in each letter gives H=11,H = 11, E=11,E = 11, L=7,L = 7, and P=10,P = 10, for a shaded total of 11+11+7+10=39.11 + 11 + 7 + 10 = 39.

The unshaded area is 7539=36.75 - 39 = 36.

Thus, the correct answer is D .

Problem 13 in Other Years

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