1997 AMC 8 第 24 题

先试着解答 1997 AMC 8 第 24 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1997 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

24.

点 CC 将直径 ACEACE 按 2:32:3 分成两段。两个半圆 ABCABC 和 CDECDE 把圆形区域分成上方阴影区域和下方区域。上方区域面积与下方区域面积的比是
Diameter ACEACE is divided at CC in the ratio 2:3.2:3. The two semicircles, ABCABC and CDE,CDE, divide the circular region into an upper (shaded) region and a lower region. The ratio of the area of the upper region to that of the lower region is
2:32:3
1:11:1
3:23:2
9:49:4
5:25:2
答案:C
知识点:圆面积面积分割
小提示:
把上方区域看成大半圆减去一个小半圆再加上另一个小半圆
Compare the upper region as a large semicircle minus one small semicircle plus the other
大提示:
选取符合 2:32:3 比例的方便长度
Choose convenient lengths in the ratio 2:32:3
解答:
取 AE=10AE=10,使 AC=4AC=4、CE=6CE=6。大半圆半径为 55,面积为 25π2\frac{25\pi}{2}。
以 ACAC 为直径的半圆半径为 22,面积为 2π2\pi;以 CECE 为直径的半圆半径为 33,面积为 9π2\frac{9\pi}{2}。
上方阴影区域面积为 25π2−2π+9π2=15π。\frac{25\pi}{2}-2\pi+\frac{9\pi}{2}=15\pi\text{。}
整个圆面积为 25π25\pi,所以下方区域面积为 25π−15π=10π25\pi-15\pi=10\pi。
所求比为 15π:10π=3:215\pi:10\pi=3:2。
所以正确答案是 C。
Choose AE=10AE=10 so that AC=4AC=4 and CE=6.CE=6. The large semicircle has radius 5,5, so its area is 25π2.\frac{25\pi}{2}.
The semicircle on ACAC has radius 22 and area 2π,2\pi, while the semicircle on CECE has radius 33 and area 9π2.\frac{9\pi}{2}.
The upper shaded region has area 25π2−2π+9π2=15π.\frac{25\pi}{2}-2\pi+\frac{9\pi}{2}=15\pi.
The whole circle has area 25π,25\pi, so the lower region has area 25π−15π=10π.25\pi-15\pi=10\pi.
The desired ratio is 15π:10π=3:2.15\pi:10\pi=3:2.
Thus, C is the correct answer.
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