1990 AMC 8 Problem 20

Below is the professionally curated solution for Problem 20 of the 1990 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1990 AMC 8 solutions, or check the answer key.

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Concepts:mean

Difficulty rating: 1060

20.

The annual incomes of 1,0001{,}000 families range from $8200 to $98,000. In error, the largest income was entered on the computer as $980,000. The difference between the mean of the incorrect data and the mean of the actual data is

$882

$980

$1078

$482,000

$882,000

Solution:

Only one entry changed. The incorrect total exceeds the actual total by $980,000$98,000=$882,000.\$980{,}000 - \$98{,}000 = \$882{,}000.

Since this extra amount is spread over 10001000 families, the means differ by $882,0001000=$882.\dfrac{\$882{,}000}{1000} = \$882.

Thus, the correct answer is A .

Problem 20 in Other Years

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