1990 AMC 8 考试题目

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1.

What is the smallest sum of two 33-digit numbers that can be obtained by placing each of the six digits 4,5,6,7,8,94, 5, 6, 7, 8, 9 into one of the six boxes of a sum of two 33-digit numbers?

947947

10371037

10471047

10561056

12451245

Answer: C
Concepts:place valueoptimization

Difficulty rating: 930

Solution:

To make the sum small, the two smallest digits go in the hundreds places, the next two in the tens places, and the two largest in the units places.

One such arrangement is 468+579=1047468 + 579 = 1047, and every arrangement of this type gives the same sum.

Thus, the correct answer is C .

2.

Which digit of .12345,.12345, when changed to 9,9, gives the largest number?

11

22

33

44

55

Answer: A

Difficulty rating: 450

Solution:

Changing a digit in the tenths place changes the number more than changing any digit farther to the right. The digit in the tenths place is 11.

Changing it gives .92345.92345, which is the largest possible result.

Thus, the correct answer is A .

3.

What fraction of the square is shaded?

13\dfrac{1}{3}

25\dfrac{2}{5}

512\dfrac{5}{12}

37\dfrac{3}{7}

12\dfrac{1}{2}

Answer: E
Concepts:areasymmetry

Difficulty rating: 730

Solution:

The diagonal from one corner to the opposite corner splits the square into two equal halves. Every shaded piece on one side of the diagonal is the mirror image of an equal unshaded piece on the other side.

So the shaded and unshaded areas are equal, and exactly 12\dfrac12 of the square is shaded.

Thus, the correct answer is E .

4.

Which of the following could not be the units digit [ones digit] of the square of a whole number?

11

44

55

66

88

Answer: E

Difficulty rating: 800

Solution:

The units digit of a square is determined by the units digit of the number squared. Squaring 00 through 99 gives units digits 0,1,4,9,6,5,6,9,4,10, 1, 4, 9, 6, 5, 6, 9, 4, 1.

So a square can only end in 0,1,4,5,6,0, 1, 4, 5, 6, or 99; it can never end in 2,3,7,2, 3, 7, or 88. Among the choices, only 88 is impossible.

Thus, the correct answer is E .

5.

Which of the following is closest to the product (.48017)(.48017)(.48017)?(.48017)(.48017)(.48017)?

0.0110.011

0.1100.110

1.101.10

11.011.0

110110

Answer: B

Difficulty rating: 800

Solution:

Since .48017.48017 is close to 12\dfrac12, the product is close to

(12)3=18=0.125.\left(\dfrac12\right)^3 = \dfrac18 = 0.125.

The choice closest to 0.1250.125 is 0.1100.110.

Thus, the correct answer is B .

6.

Which of these five numbers is the largest?

13579+1246813579 + \dfrac{1}{2468}

135791246813579 - \dfrac{1}{2468}

13579×1246813579 \times \dfrac{1}{2468}

13579÷1246813579 \div \dfrac{1}{2468}

13579.246813579.2468

Answer: D
Concepts:fraction

Difficulty rating: 730

Solution:

Choices A, B, and E are all very close to 1357913579, and choice C multiplies 1357913579 by a tiny number, making it much smaller.

Choice D divides by 12468\dfrac{1}{2468}, which is the same as multiplying by 24682468. This makes it thousands of times larger than 1357913579, so it is the largest.

Thus, the correct answer is D .

7.

When three different numbers from the set {3,2,1,4,5}\{ -3, -2, -1, 4, 5 \} are multiplied, the largest possible product is

1010

2020

3030

4040

6060

Answer: C
Concepts:optimization

Difficulty rating: 890

Solution:

For the product of three numbers to be positive, either all three are positive or exactly two are negative. There are only two positive numbers, so we must use two negatives and one positive.

To maximize, take the two most negative numbers and the largest positive: (3)(2)(5)=30(-3)(-2)(5) = 30.

Thus, the correct answer is C .

8.

A dress originally priced at $80 was put on sale at 25%25\% off. If 10%10\% tax was added to the sale price, then the total selling price of the dress was

$45

$52

$54

$66

$68

Answer: D
Concepts:percentage

Difficulty rating: 860

Solution:

The sale price is 34$80=$60.\dfrac34 \cdot \$80 = \$60.

The tax is 10%10\% of $60,\$60, which is $6,\$6, so the total is $60+$6=$66.\$60 + \$6 = \$66.

Thus, the correct answer is D .

9.

The grading scale shown is used at Jones Junior High. The fifteen scores in Mr. Freeman's class were: 89,72,54,97,77,92,85,74,75,63,84,78,71,80,90.89, 72, 54, 97, 77, 92, 85, 74, 75, 63, 84, 78, 71, 80, 90.

The grading scale is A: 93100,\text{A: } 93\text{--}100, B: 8592,\text{B: } 85\text{--}92, C: 7584,\text{C: } 75\text{--}84, D: 7074,\text{D: } 70\text{--}74, F: 069.\text{F: } 0\text{--}69.

In Mr. Freeman's class, what percent of the students received a grade of C?

20%20\%

25%25\%

30%30\%

3313%33\dfrac{1}{3}\%

40%40\%

Answer: D

Difficulty rating: 860

Solution:

A grade of C corresponds to scores from 7575 to 8484. The qualifying scores are 77,75,84,78,8077, 75, 84, 78, 80, which is 55 students.

So the percent is 515=13=3313%.\dfrac{5}{15} = \dfrac13 = 33\dfrac13\%.

Thus, the correct answer is D .

10.

On this monthly calendar, the date behind one of the letters is added to the date behind CC. If this sum equals the sum of the dates behind AA and BB, then the letter is

PP

QQ

RR

SS

TT

Answer: A
Concepts:date and time

Difficulty rating: 1090

Solution:

Moving one column right adds 11 to the date, and moving one row down adds 77. Let CC have date nn. Then AA, one column to the right, is n+1n+1. The letter PP sits two rows directly below CC, so P=n+14P = n+14, and BB, one column left of PP in the bottom row, is n+13n+13.

We need a letter whose date dd satisfies d+n=(n+1)+(n+13)d + n = (n+1) + (n+13), so d=n+14d = n + 14. That date is behind PP.

Thus, the correct answer is A .

11.

The numbers on the faces of this cube are consecutive whole numbers. The sums of the two numbers on each of the three pairs of opposite faces are equal. The sum of the six numbers on this cube is

7575

7676

7878

8080

8181

Answer: E

Difficulty rating: 1090

Solution:

The six consecutive numbers include 11,14,1511, 14, 15, so five of the faces are 11,12,13,14,1511, 12, 13, 14, 15 and the sixth is 1010 or 1616.

If the sixth were 1010, equal opposite sums would force the pairs (10,15),(11,14),(12,13)(10,15), (11,14), (12,13), making 1111 and 1414 opposite. But the figure shows 11,14,1511, 14, 15 meeting at one corner, so no two of them are opposite. Hence the sixth number is 1616, with pairs (11,16),(12,15),(13,14)(11,16), (12,15), (13,14), each summing to 2727.

The total is 327=813 \cdot 27 = 81.

Thus, the correct answer is E .

12.

There are twenty-four 44-digit whole numbers that use each of the four digits 2,4,5,2, 4, 5, and 77 exactly once. Listed in numerical order from smallest to largest, the number in the 1717th position in the list is

45274527

57245724

57425742

72457245

75247524

Answer: B

Difficulty rating: 1030

Solution:

Each leading digit accounts for 66 of the 2424 numbers. Positions 1166 begin with 22, positions 771212 begin with 44, and positions 13131818 begin with 55.

So the 1717th number is the 55th one beginning with 55: 5247,5274,5427,5472,57245247, 5274, 5427, 5472, 5724. The fifth is 57245724.

Thus, the correct answer is B .

13.

One proposal for new postage rates for a letter was 3030¢ for the first ounce and 2222¢ for each additional ounce (or fraction of an ounce). The postage for a letter weighing 4.54.5 ounces was

9696¢

$1.07

$1.18

$1.20

$1.40

Answer: C

Difficulty rating: 930

Solution:

The first ounce costs 3030¢. The remaining 3.53.5 ounces are charged as 44 additional ounces, since any fraction rounds up to a full ounce.

That is 4224 \cdot 22¢ =88= 88¢, so the total is 3030¢ +88+ 88¢ =118= 118¢ =$1.18.= \$1.18.

Thus, the correct answer is C .

14.

A bag contains only blue balls and green balls. There are 66 blue balls. If the probability of drawing a blue ball at random from this bag is 14,\dfrac14, then the number of green balls in the bag is

1212

1818

2424

3030

3636

Answer: B

Difficulty rating: 860

Solution:

Since blue balls make up 14\dfrac14 of the bag and there are 66 of them, the total is 64=246 \cdot 4 = 24 balls.

So the number of green balls is 246=1824 - 6 = 18.

Thus, the correct answer is B .

15.

The area of this figure is 100 cm2.100 \text{ cm}^2. Its perimeter is

(The figure consists of four identical squares.)

20 cm20 \text{ cm}

25 cm25 \text{ cm}

30 cm30 \text{ cm}

40 cm40 \text{ cm}

50 cm50 \text{ cm}

Answer: E
Concepts:areaperimeter

Difficulty rating: 930

Solution:

Each of the four squares has area 1004=25 cm2\dfrac{100}{4} = 25 \text{ cm}^2, so each side is 5 cm.5 \text{ cm}.

The outline of this staircase shape is made up of 1010 such sides, so the perimeter is 105=50 cm.10 \cdot 5 = 50 \text{ cm}.

Thus, the correct answer is E .

16.

What is the value of the following expression?

19901980+19701960+20+101990 - 1980 + 1970 - 1960 + \cdots - 20 + 10

990-990

10-10

990990

10001000

19901990

Answer: D

Difficulty rating: 1060

Solution:

Group the terms as (19901980)+(19701960)++(3020)+10.(1990 - 1980) + (1970 - 1960) + \cdots + (30 - 20) + 10. Each parenthesized pair equals 1010.

The first elements 1990,1970,,301990, 1970, \ldots, 30 number 9999, so there are 9999 pairs, giving 990990, plus the leftover +10+10 at the end for a total of 10001000.

Thus, the correct answer is D .

17.

A straight concrete sidewalk is to be 33 feet wide, 6060 feet long, and 33 inches thick. How many cubic yards of concrete must a contractor order for the sidewalk if concrete must be ordered in a whole number of cubic yards?

22

55

1212

2020

more than 2020

Answer: A

Difficulty rating: 1140

Solution:

The thickness is 33 inches =14= \dfrac14 foot, so the volume is 36014=453 \cdot 60 \cdot \dfrac14 = 45 cubic feet.

Since 11 cubic yard =27= 27 cubic feet, this is 4527=123\dfrac{45}{27} = 1\dfrac23 cubic yards. Rounding up to a whole number, the contractor must order 22 cubic yards.

Thus, the correct answer is A .

18.

Every corner of a rectangular prism is cut off by a straight slice through the three edges meeting at that corner, removing a small triangular piece at each of the eight corners. How many edges does the new figure have?

2424

3030

3636

4242

4848

Answer: C
Concepts:polyhedron

Difficulty rating: 1180

Solution:

A rectangular prism starts with 1212 edges, and cutting corners only shortens them without removing any.

Each of the 88 corner cuts creates a small triangular face with 33 new edges, adding 83=248 \cdot 3 = 24 edges. The total is 12+24=3612 + 24 = 36.

Thus, the correct answer is C .

19.

There are 120120 seats in a row. What is the fewest number of seats that must be occupied so the next person to be seated must sit next to someone?

3030

4040

4141

6060

119119

Answer: B

Difficulty rating: 1090

Solution:

To force the next person next to someone, every empty seat must be adjacent to an occupied one. The most efficient way is to seat people in a repeating pattern of occupied-empty-empty, filling the middle seat of every group of three.

With 120120 seats, this uses 1203=40\dfrac{120}{3} = 40 occupied seats.

Thus, the correct answer is B .

20.

The annual incomes of 1,0001{,}000 families range from $8200 to $98,000. In error, the largest income was entered on the computer as $980,000. The difference between the mean of the incorrect data and the mean of the actual data is

$882

$980

$1078

$482,000

$882,000

Answer: A
Concepts:mean

Difficulty rating: 1060

Solution:

Only one entry changed. The incorrect total exceeds the actual total by $980,000$98,000=$882,000.\$980{,}000 - \$98{,}000 = \$882{,}000.

Since this extra amount is spread over 10001000 families, the means differ by $882,0001000=$882.\dfrac{\$882{,}000}{1000} = \$882.

Thus, the correct answer is A .

21.

A list of 88 numbers is formed by beginning with two given numbers. Each new number in the list is the product of the two previous numbers. Find the first number if the last three are 16,64,102416, 64, 1024:

?,x,x,x,x,16,64,1024?, \underline{\phantom{x}}, \underline{\phantom{x}}, \underline{\phantom{x}}, \underline{\phantom{x}}, 16, 64, 1024

164\dfrac{1}{64}

14\dfrac{1}{4}

11

22

44

Answer: B

Difficulty rating: 1200

Solution:

Since each term is the product of the two before it, dividing any term by the term just before it recovers the term two positions earlier. Working backwards from the last three terms 16,64,102416, 64, 1024:

64÷16=4,16÷4=4,4÷4=1,4÷1=4,1÷4=14.64 \div 16 = 4, \quad 16 \div 4 = 4, \quad 4 \div 4 = 1, \quad 4 \div 1 = 4, \quad 1 \div 4 = \dfrac14.

These fill in the earlier terms, giving the full list 14,4,1,4,4,16,64,1024\dfrac14, 4, 1, 4, 4, 16, 64, 1024. The first number is 14\dfrac14.

Thus, the correct answer is A .

22.

Several students are seated at a large circular table. They pass around a bag containing 100100 pieces of candy. Each person receives the bag, takes one piece of candy, and then passes the bag to the next person. If Chris takes the first and the last piece of candy, then the number of students at the table could be

1010

1111

1919

2020

2525

Answer: B

Difficulty rating: 1140

Solution:

Chris takes the first piece, and then the bag goes around until Chris takes the last (100100th) piece. So the 9999 pieces after Chris's first must be exactly a whole number of trips around the table back to Chris.

This means the number of students divides 9999. Among the choices, only 1111 divides 9999.

Thus, the correct answer is B .

23.

The graph relates the distance traveled (in miles) to the time elapsed (in hours) on a trip taken by an experimental airplane. During which hour was the average speed of this airplane the largest?

first (0-1)(0\text{-}1)

second (1-2)(1\text{-}2)

third (2-3)(2\text{-}3)

ninth (8-9)(8\text{-}9)

last (11-12)(11\text{-}12)

Answer: B

Difficulty rating: 970

Solution:

The average speed during any single hour equals the distance the airplane covers in that hour, which on the graph is the vertical rise of the curve over that one-hour interval. So the largest average speed happens during the hour where the curve is steepest.

From t=1t=1 to t=2t=2 the curve climbs from about 500500 miles to about 10001000 miles, a rise of roughly 500500 miles, giving an average speed near 500500 mph. During every other hour the curve rises by less than 350350 miles, so those average speeds are all smaller. The steepest climb, and hence the largest average speed, is during the second hour.

Thus, the correct answer is B .

24.

Three triangles and a diamond balance nine dots. Also, one triangle balances a diamond and a dot. How many dots will balance two diamonds?

11

22

33

44

55

Answer: C

Difficulty rating: 1120

Solution:

Let a triangle, diamond, and dot weigh tt, dd, and 11. The conditions give 3t+d=93t + d = 9 and t=d+1t = d + 1.

Substituting, 3(d+1)+d=93(d+1) + d = 9, so 4d+3=94d + 3 = 9 and d=32d = \dfrac32. Then two diamonds weigh 2d=32d = 3 dots.

Thus, the correct answer is C .

25.

How many different patterns can be made by shading exactly two of the nine unit squares in a 3×33 \times 3 grid? Patterns that can be matched by flips and/or turns are not considered different.

33

66

88

1212

1818

Answer: C

Difficulty rating: 1470

Solution:

Classify the two shaded squares up to rotations and reflections. Patterns that include a corner: two adjacent corners (same edge), two diagonally opposite corners, corner with the center, corner with an adjacent edge-middle, and corner with a far edge-middle. That is 55 patterns.

Patterns with no corner: two adjacent edge-middles, two opposite edge-middles, and an edge-middle with the center. That is 33 more.

In total there are 5+3=85 + 3 = 8 distinct patterns.

Thus, the correct answer is C .