1990 AMC 8 Problem 12

Below is the professionally curated solution for Problem 12 of the 1990 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1990 AMC 8 solutions, or check the answer key.

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Concepts:permutationssystematic listing

Difficulty rating: 1030

12.

There are twenty-four 44-digit whole numbers that use each of the four digits 2,4,5,2, 4, 5, and 77 exactly once. Listed in numerical order from smallest to largest, the number in the 1717th position in the list is

45274527

57245724

57425742

72457245

75247524

Solution:

Each leading digit accounts for 66 of the 2424 numbers. Positions 1166 begin with 22, positions 771212 begin with 44, and positions 13131818 begin with 55.

So the 1717th number is the 55th one beginning with 55: 5247,5274,5427,5472,57245247, 5274, 5427, 5472, 5724. The fifth is 57245724.

Thus, the correct answer is B .

Problem 12 in Other Years

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