2006 AMC 8 Problem 12

Below is the professionally curated solution for Problem 12 of the 2006 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.

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Concepts:meanpercentage

Difficulty rating: 1100

12.

Antonette gets 70%70 \% on a 1010-problem test, 80%80 \% on a 2020-problem test and 90%90 \% on a 3030-problem test. If the three tests are combined into one 6060-problem test, which percent is closest to her overall score?

4040

7777

8080

8383

8787

Solution:

Antonette got 0.710=70.7\cdot 10=7 questions right on the first test. Similarly, she got 0.820=160.8\cdot 20=16 and 0.930=270.9\cdot 30=27 problems right on her second and third tests.

Adding these up yields 5050 correct questions. Her score on the combined test would have been 1005060=8313%100\cdot \dfrac{50}{60}=83\frac{1}{3}\%, closest to 83%83\%.

Thus, D is the correct answer.

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