2010 AMC 10A Problem 17

Below is the professionally curated solution for Problem 17 of the 2010 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

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Concepts:volumeinclusion-exclusion3D geometry

Difficulty rating: 1790

17.

A solid cube has side length 33 inches. A 22-inch by 22-inch square hole is cut into the center of each face. The edges of each cut are parallel to the edges of the cube, and each hole goes all the way through the cube. What is the volume, in cubic inches, of the remaining solid?

77

88

1010

1212

1515

Solution:

Note that all the cut out solids intersect in the middle of the cube.

This region of intersection is a cube with side length 2.2. Then the volume of the cutout region is 3223223=3616=20. \begin{align*}3 \cdot 2 \cdot 2 \cdot 3 - 2 \cdot 2^3 &= 36 - 16 \\&= 20.\end{align*}

We have to subtract out the center region twice since it is included in all 33 regions.

The remaining volume is then 3320=2720=7. 3^3 - 20 = 27 - 20 = 7.

Thus, A is the correct answer.

Problem 17 in Other Years