2004 AMC 10A 第 14 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

14.

Paula 钱包中所有一分、五分、十分和二十五分硬币的平均面值是 2020 美分。如果她再多一枚二十五分硬币,平均面值会变为 2121 美分。她钱包中有多少枚十分硬币?

The average value of all the pennies, nickels, dimes, and quarters in Paula's purse is 2020 cents. If she had one more quarter, the average value would be 2121 cents. How many dimes does she have in her purse?

00

11

22

33

44

答案:A
知识点:平均数钱币一次方程
难度评级:1450
解答:

若有 nn 枚硬币,总面值为 20n20n 美分。方程 给出 n=4n = 420n+25=21(n+1), 20n + 25 = 21(n + 1),

四枚硬币总值 1010 美分,只能是三枚二十五分硬币和一枚五分硬币。因此十分硬币的数量为 002(25)+2(10)=702(25)+2(10)=70 55

所以正确答案是 A

With nn coins the total value is 20n20n cents. Adding a quarter gives 20n+25=21(n+1), 20n + 25 = 21(n + 1), so n=4.n = 4.

If there were at most two quarters, the other coins would be worth at most 1010 cents each, so four coins would total at most 2(25)+2(10)=702(25)+2(10)=70 cents. Thus there must be three quarters, leaving 55 cents for the fourth coin. The purse contains three quarters and one nickel, so it has 00 dimes.

Thus, the correct answer is A.

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