2003 AMC 10A 第 17 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

17.

一个等边三角形周长的英寸数等于其外接圆面积的平方英寸数。这个圆的半径是多少英寸?

The number of inches in the perimeter of an equilateral triangle equals the number of square inches in the area of its circumscribed circle. What is the radius, in inches, of the circle?

32π\dfrac{3\sqrt{2}}{\pi}

33π\dfrac{3\sqrt{3}}{\pi}

3\sqrt{3}

6π\dfrac{6}{\pi}

3π\sqrt{3}\pi

答案:B
知识点:等边三角形外接圆、外心与外接圆半径特殊直角三角形
难度评级:1600
解答:

设边长为 ss,外接圆半径为 RR。由等边三角形中的 3030-6060-9090 三角形,R=s3R = \dfrac{s}{\sqrt{3}},所以 s=R3s = R\sqrt{3}

周长为 3s=3R33s = 3R\sqrt{3},圆面积为 πR2\pi R^2

令二者相等,3R3=πR23R\sqrt{3} = \pi R^2,所以 R=33πR = \dfrac{3\sqrt{3}}{\pi}

所以正确答案是 B

Let the side length be ss and the circumradius be R.R. From a 3030-6060-9090 triangle formed by the center and a side, R=s3,R = \dfrac{s}{\sqrt{3}}, so s=R3.s = R\sqrt{3}.

The perimeter is 3s=3R33s = 3R\sqrt{3} and the circle's area is πR2.\pi R^2.

Setting them equal, 3R3=πR2,3R\sqrt{3} = \pi R^2, so R=33π.R = \dfrac{3\sqrt{3}}{\pi}.

Thus, the correct answer is B.

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