2013 AMC 12B Problem 1

Below is the professionally curated solution for Problem 1 of the 2013 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 12B solutions, or check the answer key.

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Concepts:meanlinear equation

Difficulty rating: 920

1.

On a particular January day, the high temperature in Lincoln, Nebraska, was 1616 degrees higher than the low temperature, and the average of the high and low temperatures was 3.3^\circ. In degrees, what was the low temperature in Lincoln that day?

13-13

8-8

5-5

3-3

1111

Solution:

The high exceeds the low by 16,16, so the low is 88 below the average. Since the average is 3,3^\circ, the low temperature is 38=5.3 - 8 = -5^\circ. Thus, the correct answer is C.

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