1995 AMC 12 Problem 1

Attempt Problem 1 of the 1995 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1995 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

Kim earned scores of $87,$ $83$ and $88$ on her first three mathematics examinations. If Kim receives a score of $90$ on the fourth exam, then her average will

remain the same

increase by $1$

increase by $2$

increase by $3$

increase by $4$

Answer: B

Concepts:arithmetic mean

Difficulty rating: 690

Small Hint:

Compare $90$ with the average of the first three scores

Big Hint:

Find the old and new totals before dividing by the number of exams

Solution:

The first three scores total $87+83+88=258,$ so their average is $\frac{258}{3}=86.$ With the fourth score, the total is $348,$ and the new average is $\frac{348}{4}=87.$ It increases by $1,$ so the correct answer is B.

Full Exam

Problem 2#2 →

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