2010 AMC 12A Problem 1

Below is the professionally curated solution for Problem 1 of the 2010 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 12A solutions, or check the answer key.

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Concepts:whole number operationsorder of operations

Difficulty rating: 770

1.

What is (20(2010201))+(2010(20120))?(20-(2010-201))+(2010-(201-20))?

4020-4020

00

4040

401401

40204020

Solution:

Distributing the negative signs gives (202010+201)+(2010201+20)=40.(20-2010+201)+(2010-201+20)=40.

Thus, C is the correct answer.

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