2005 AMC 12A Problem 13

Attempt Problem 13 of the 2005 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 12A solutions, or check the answer key.

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13.

In the five-sided star shown, the letters A,A, B,B, C,C, D,D, and EE are replaced by the numbers 3,5,6,7,3, 5, 6, 7, and 9,9, although not necessarily in that order. The sums of the numbers at the ends of the line segments AB,AB, BC,BC, CD,CD, DE,DE, and EAEA form an arithmetic sequence, although not necessarily in that order. What is the middle term of the arithmetic sequence?

99

1010

1111

1212

1313

Answer: D
Concepts:arithmetic sequencedouble counting
Difficulty rating: 1620
Solution:

Every number appears as an endpoint of exactly two of the five segments, so the total of the five sums is 2(3+5+6+7+9)=60. 2(3 + 5 + 6 + 7 + 9) = 60.

The middle term of a five-term arithmetic sequence is its mean, namely 60÷5=12.60 \div 5 = 12.

Thus, the correct answer is D.

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