2003 AMC 12B Problem 13

Below is the professionally curated solution for Problem 13 of the 2003 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 12B solutions, or check the answer key.

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Concepts:conespherevolume

Difficulty rating: 1490

13.

An ice cream cone consists of a sphere of vanilla ice cream and a right circular cone that has the same diameter as the sphere. If the ice cream melts, it will exactly fill the cone. Assume that the melted ice cream occupies 75%75\% of the volume of the frozen ice cream. What is the ratio of the cone's height to its radius?

2:12 : 1

3:13 : 1

4:14 : 1

16:316 : 3

6:16 : 1

Solution:

Let rr be the common radius and hh the cone's height. The melted ice cream fills the cone, so 3443πr3=13πr2h. \frac{3}{4}\cdot\frac{4}{3}\pi r^3 = \frac{1}{3}\pi r^2 h.

This simplifies to πr3=13πr2h,\pi r^3 = \dfrac{1}{3}\pi r^2 h, so h=3r,h = 3r, a ratio of 3:1.3 : 1.

Thus, the correct answer is B.

Problem 13 in Other Years