2020 AMC 12A Problem 13

Below is the professionally curated solution for Problem 13 of the 2020 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 12A solutions, or check the answer key.

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Concepts:radicalexponent

Difficulty rating: 1590

13.

There are integers a,a, b,b, and c,c, each greater than 1,1, such that NNNcba=N2536\sqrt[a]{N \sqrt[b]{N \sqrt[c]{N}}} = \sqrt[36]{N^{25}} for all N>1.N \gt 1. What is b?b?

22

33

44

55

66

Solution:

The left side equals NN raised to the exponent 1a+1ab+1abc,\dfrac{1}{a} + \dfrac{1}{ab} + \dfrac{1}{abc}, which must equal 2536.\dfrac{25}{36}.

Trying a=2a = 2 leaves 12b+12bc=253612=736.\dfrac{1}{2b} + \dfrac{1}{2bc} = \dfrac{25}{36} - \dfrac12 = \dfrac{7}{36}.

Then 12b(1+1c)=736.\dfrac{1}{2b}\left(1 + \dfrac1c\right) = \dfrac{7}{36}. Taking b=3b = 3 gives 1+1c=76,1 + \dfrac1c = \dfrac{7}{6}, so c=6.c = 6.

All three are integers greater than 1,1, and b=3.b = 3.

Thus, B is the correct answer.

Problem 13 in Other Years