2006 AMC 12B Problem 13

Below is the professionally curated solution for Problem 13 of the 2006 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 12B solutions, or check the answer key.

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Concepts:rhombusequilateral trianglearea decomposition

Difficulty rating: 1660

13.

Rhombus ABCDABCD is similar to rhombus BFDE.BFDE. The area of rhombus ABCDABCD is 24,24, and BAD=60.\angle BAD = 60^\circ. What is the area of rhombus BFDE?BFDE?

66

434\sqrt{3}

88

99

636\sqrt{3}

Solution:

Because BAD=60\angle BAD = 60^\circ and AB=AD,AB = AD, triangle ABDABD is equilateral. The diagonals ACAC and BDBD together with segments BE,BE, DFDF split ABCDABCD into six congruent triangles.

Each of these triangles has area 246=4.\dfrac{24}{6} = 4.

Rhombus BFDEBFDE is the union of BED\triangle BED and BFD,\triangle BFD, two of them, so its area is 8.8.

Thus, the correct answer is C.

Problem 13 in Other Years