2000 AMC 12 Problem 13

Attempt Problem 13 of the 2000 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 12 solutions, or check the answer key.

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13.

One morning each member of Angela's family drank an 88-ounce mixture of coffee with milk. The amounts of coffee and milk varied from cup to cup, but were never zero. Angela drank a quarter of the total amount of milk and a sixth of the total amount of coffee. How many people are in the family?

33

44

55

66

77

Answer: C
Concepts:fractionlinear equationbounding to limit cases
Difficulty rating: 1710
Solution:

Measure amounts in 88-ounce cups, so Angela's cup holds cc coffee and mm milk with c+m=1.c + m = 1.

Since Angela drank a sixth of the coffee, the total coffee is 6c6c; since she drank a quarter of the milk, the total milk is 4m.4m. The number of people equals the total number of cups, 6c+4m=6c+4(1c)=4+2c. \begin{aligned} 6c + 4m &= 6c + 4(1 - c) \\ &= 4 + 2c. \end{aligned}

This is an integer only when 2c2c is an integer, and since 0<c<10 \lt c \lt 1 this forces c=12,c = \tfrac12, giving 4+1=54 + 1 = 5 people.

Thus, the correct answer is C.

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