2018 AMC 10B Problem 9

Attempt Problem 9 of the 2018 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

The faces of each of 77 standard dice are labeled with the integers from 11 to 6.6. Let pp be the probability that when all 77 dice are rolled, the sum of the numbers on the top faces is 10.10. What other sum occurs with the same probability p?p?
1313
2626
3232
3939
4242
Answer: D
Concepts:dice (probability)bijectionsymmetry
Small hint:
Replacing each die value kk by 7−k7 - k pairs up equally likely outcomes
Big hint:
This replacement sends a total of ss to a total of 49−s49 - s
Solution:
Replace each die’s value kk by 7−k.7 - k. This pairs up outcomes one-to-one and keeps their probabilities, and it sends a total of ss to 7⋅7−s=49−s.7 \cdot 7 - s = 49 - s. So the sums ss and 49−s49 - s are equally likely. The partner of 1010 is 49−10=39.49 - 10 = 39. Thus, D is the correct answer.
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