2017 AMC 10B Problem 1

Attempt Problem 1 of the 2017 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Mary thought of a positive two-digit number. She multiplied it by 33 and added 11.11. Then she switched the digits of the result, obtaining a number between 7171 and 75,75, inclusive. What was Mary’s number?
1111
1212
1313
1414
1515
Answer: B
Concepts:digitsdivisibilitywork backwards
Small hint:
Work backward from the possible reversed results
Big hint:
After reversing and subtracting 1111, check divisibility by 33
Solution:
Work backward from the possible results. Reversing 71,72,73,74,7571,72,73,74,75 gives 17,27,37,47,57,17,27,37,47,57, respectively. Subtracting 1111 gives 6,16,26,36,46.6,16,26,36,46. Only 66 and 3636 are divisible by 3,3, and only 36÷3=1236\div3=12 is a two-digit number.
Thus, the correct answer is B .
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.