2017 AMC 10A Problem 2

Attempt Problem 2 of the 2017 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

Pablo buys popsicles for his friends. The store sells single popsicles for $1\$1 each, 33-popsicle boxes for $2\$2 each, and 55-popsicle boxes for $3.\$3. What is the greatest number of popsicles that Pablo can buy with $8?\$8?
88
1111
1212
1313
1515
Answer: D
Concepts:moneyoptimization
Small hint:
Compare popsicles per dollar for the three buying options
Big hint:
First decide the best use of $6\$6, then spend the remaining $2\$2
Solution:
The $3\$3 boxes give us the most popsicles per dollar, so we want to buy as many of those as possible.
We can buy two of those, getting 5⋅2=105 \cdot 2 = 10 popsicles with $8−$6=$2\$8 - \$6 = \$2 remaining.
The $1\$1 single popsicles are the worst deal, so Pablo should spend the rest of his money on the 33-popsicle box.
He then ends up with 10+3=1310 + 3 = 13 popsicles.
Thus, D is the correct answer.
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