2016 AMC 10A Problem 20

Below is the professionally curated solution for Problem 20 of the 2016 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10A solutions, or check the answer key.

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Concepts:stars and barscombinations

Difficulty rating: 1660

20.

For some particular value of N,N, when (a+b+c+d+1)N(a+b+c+d+1)^N is expanded and like terms are combined, the resulting expression contains exactly 10011001 terms that include all four variables a,b,c,a, b,c, and d,d, each to some positive power. What is N?N?

99

1414

1616

1717

1919

Solution:

A term that includes all four variables has form avbwcxdya^vb^wc^xd^y, with v,w,x,y1v,w,x,y\ge1, multiplied by some power of 11. If that power is zz, then v+w+x+y+z=N.v+w+x+y+z=N.

After subtracting 11 from each of v,w,x,yv,w,x,y, this becomes a nonnegative stars-and-bars count with 55 variables summing to N4N-4. The number of such terms is (N4).\binom{N}{4}.

Since (144)=1001\binom{14}{4}=1001, we get N=14N=14.

Thus, the correct answer is B.

Problem 20 in Other Years