2025 AMC 10A Problem 20

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Concepts:tangent linecoordinate geometryquadratic

Difficulty rating: 2080

20.

A silo (right circular cylinder) with diameter 2020 meters stands in a field. MacDonald is located 2020 meters west and 1515 meters south of the center of the silo. McGregor is located 2020 meters east and g>0g \gt 0 meters south of the center of the silo. The line of sight between MacDonald and McGregor is tangent to the silo. The value of gg can be written as abcd,\dfrac{a\sqrt{b} - c}{d}, where a,b,c,a, b, c, and dd are positive integers, bb is not divisible by the square of any prime, and dd is relatively prime to the greatest common divisor of aa and c.c. What is a+b+c+d?a + b + c + d?

119119

120120

121121

122122

123123

Solution:

Put the silo's center at the origin with radius 10.10. Then MacDonald is at D=(20,15)D = (-20, -15) and McGregor at G=(20,g).G = (20, -g). The tangent length from DD is DT=DS2102=252100=525,DT = \sqrt{DS^2 - 10^2} = \sqrt{25^2 - 100} = \sqrt{525}, and from GG it's TG=g2+202102.TG = \sqrt{g^2 + 20^2 - 10^2}. The tangent point TT sits between the two men, so DG=DT+TG.DG = DT + TG. But also DG=402+(15g)2.DG = \sqrt{40^2 + (15 - g)^2}. Square twice and simplify: 3g2+150g925=0,3g^2 + 150g - 925 = 0, which gives g=2021753.g = \frac{20\sqrt{21} - 75}{3}. So a+b+c+d=20+21+75+3=119.a + b + c + d = 20 + 21 + 75 + 3 = 119. Therefore, the answer is A.

Problem 20 in Other Years