2016 AMC 10A Problem 1

Attempt Problem 1 of the 2016 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

What is the value of 11!−10!9!?\dfrac{11!-10!}{9!}?
9999
100100
110110
121121
132132
Answer: B
Concepts:factorialfactoring
Small hint:
Factor 10!10! or 9!9! from the numerator
Big hint:
Use 11!=11⋅10⋅9!11!=11\cdot10\cdot9!
Solution:
We can factor a 9!9! out of the numerator and simplify. 9!(11⋅10−10)9!=11⋅10−10=110−10=100.\begin{aligned} \dfrac{9!(11 \cdot 10 - 10)}{9!} &=11 \cdot 10 - 10 \\&= 110 - 10 \\&= 100. \end{aligned} Thus, the correct answer is B .
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