2014 AMC 10A Problem 11

Attempt Problem 11 of the 2014 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

A customer who intends to purchase an appliance has three coupons, only one of which may be used:
Coupon 1:1: 10%10\% off the listed price if the listed price is at least $50\$50
Coupon 2:2: $20\$ 20 off the listed price if the listed price is at least $100\$100
Coupon 3:3: 18%18\% off the amount by which the listed price exceeds $100\$100
For which of the following listed prices will coupon 11 offer a greater price reduction than either coupon 22 or coupon 3?3?
$179.95\$ 179.95
$199.95\$ 199.95
$219.95\$ 219.95
$239.95\$ 239.95
$259.95\$ 259.95
Answer: C
Concepts:inequalitypercentage
Small hint:
Compare the actual dollar discount, not the final price
Big hint:
Solve the inequalities where coupon 11 beats coupons 22 and 33
Solution:
Let us analyze what these coupons do to an arbitrary price, x.x.
Coupon 11 changes this price to 0.9x.0.9x. Coupon 22 changes the price to x−20.x - 20. Coupon 33 changes the price to x−0.18(x−100)=0.82x+18. x - 0.18(x - 100) = 0.82x + 18.
We want 0.9x<x−20 0.9x \lt x - 20 and 0.9x<0.82x+18. 0.9x \lt 0.82x + 18. Solving both gives us 200<x<225.200 \lt x \lt 225.
The only answer choice that works is $219.95.\$ 219.95.
Thus, C is the correct answer.
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