2017 AMC 10A Problem 11

Below is the professionally curated solution for Problem 11 of the 2017 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10A solutions, or check the answer key.

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Concepts:volumecylindersphere

Difficulty rating: 1540

11.

The region consisting of all points in three-dimensional space within 33 units of line segment AB\overline{AB} has volume 216π.216\pi. What is the length AB?AB?

66

1212

1818

2020

2424

Solution:

Recall that all the points at most a fixed distance rr away from a point form a sphere.

At the end points of this line segment, we can visualize two hemispheres being formed at each end.

All the points in the middle also have spheres forming around them, but they get merged into the ones right next to them.

This means that the middle section forms a cylinder with radius 3.3. The two hemispheres form a sphere with radius 3,3, and therefore a volume of 43π33=2743π=36π. \dfrac{4}{3} \pi 3^3 = 27 \cdot \dfrac{4}{3} \pi = 36 \pi. This means that the cylinder has a volume of 216π36π=180π.216 \pi - 36 \pi = 180 \pi. We know the base area is 9π,9 \pi, so if hh is AB,AB, then the volume is π32h=180π9hπ=180πh=20. \begin{align*} \pi 3^2 h &= 180\pi \\9h \pi &= 180 \pi \\ h &= 20. \end{align*}

Thus, D is the correct answer.

Problem 11 in Other Years