2021 AMC 10A Fall Problem 11

Below is the professionally curated solution for Problem 11 of the 2021 AMC 10A Fall, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Fall solutions, or check the answer key.

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Concepts:relative speeddistance rate and timeratio and proportion

Difficulty rating: 1370

11.

Emily sees a ship traveling at a constant speed along a straight section of a river. She walks parallel to the riverbank at a uniform rate faster than the ship. She counts 210210 equal steps walking from the back of the ship to the front. Walking in the opposite direction, she counts 4242 steps of the same size from the front of the ship to the back. In terms of Emily's equal steps, what is the length of the ship?

7070

8484

9898

105105

126126

Solution:

Let xx be the length of the ship. Then in the time that Emily moves 210210 steps, the ship moves 210x210 - x steps.

In the time that Emily moves 4242 steps, the ship moves x42x - 42 steps. Since the ship and Emily move at a constant rate 210210x=42x42. \dfrac{210}{210 - x} = \dfrac{42}{x - 42}. Cross-multiplying yields 210x21042=2104242x 210x - 210 \cdot 42 = 210 \cdot 42 - 42x 426x=242210 42 \cdot 6 x = 2 \cdot 42 \cdot 210 x=70. x = 70.

Thus, A is the correct answer.

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