2012 AMC 10B Problem 2

Attempt Problem 2 of the 2012 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

A circle of radius 55 is inscribed in a rectangle as shown. The ratio of the length of the rectangle to its width is 2:1.2:1. What is the area of the rectangle?
50 50
100 100
125 125
150 150
200 200
Answer: E
Concepts:circlerectangleratio and proportion
Small hint:
The rectangle width is the circle diameter
Big hint:
Use the 2:12:1 length-to-width ratio after finding the width
Solution:
The smaller side of the rectangle is equal to the diameter, which is 2r=2⋅5=10.2r=2\cdot 5=10.
Due to the 2:12:1 ratio, the long side is 10⋅2=20.10\cdot 2=20.
Therefore, the area is 20⋅10=200.20\cdot 10=200.
Thus, the correct answer is E .
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.