2012 AMC 10A Problem 2

Attempt Problem 2 of the 2012 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

A square with side length 88 is cut in half, creating two congruent rectangles. What are the dimensions of one of these rectangles?
2 by 42 \text{ by } 4
2 by 62 \text{ by } 6
2 by 82 \text{ by } 8
4 by 44 \text{ by } 4
4 by 84 \text{ by } 8
Answer: E
Concepts:square (geometry)rectangle
Small hint:
One side of each rectangle stays 88
Big hint:
The other side is half of the square side length
Solution:
Note that the one of the sides remains the same as the original square.
This means that one dimension is 8.8. The other dimension is the original side cut in half, which is 4.4.
Thus, E is the correct answer.
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