2010 AMC 10A Problem 9

Attempt Problem 9 of the 2010 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

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9.

A palindrome, such as 83438,83438, is a number that remains the same when its digits are reversed. The numbers xx and x+32x + 32 are three-digit and four-digit palindromes, respectively. What is the sum of the digits of x?x?
2020
2121
2222
2323
2424
Answer: E
Concepts:palindromedigitsbounding to limit cases
Small hint:
Bound the four-digit palindrome between 10001000 and 10311031
Big hint:
Find the only palindrome in that interval, then subtract 3232
Solution:
Note that xx is at most 999.999. This means that x+32x + 32 has a maximum of 1031.1031.
Similarly, we have that the minimum value of x+32x + 32 is 1000.1000.
The only palindrome in this range is 1001,1001, so this is what x+32x + 32 equals.
Then x+32=1001 x + 32 = 1001 x=969. x = 969.
The sum of the digits is then 9+6+9=24. 9 + 6 + 9 = 24.
Thus, E is the correct answer.
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