2009 AMC 10B Problem 2

Attempt Problem 2 of the 2009 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

Which of the following is equal to 13−14  12−13 ?\dfrac{\frac13-\frac14\ }{\ \frac12-\frac13\ }?
14\dfrac14
13\dfrac13
12\dfrac12
23\dfrac23
34\dfrac34
Answer: C
Concepts:fraction
Small hint:
Multiply the numerator and denominator by 1212
Big hint:
13−14=112\dfrac13-\dfrac14=\dfrac1{12} and 12−13=16\dfrac12-\dfrac13=\dfrac16
Solution:
The least common denominator of the small fractions is 12,12, so multiply top and bottom by 12:12: 13−1412−13=4−36−4=12. \dfrac{\frac13-\frac14}{\frac12-\frac13}=\dfrac{4-3}{6-4}=\dfrac12.
Thus, the correct answer is C.
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