2009 AMC 10A Problem 2

Attempt Problem 2 of the 2009 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

Four coins are picked out of a piggy bank that contains a collection of pennies, nickels, dimes, and quarters. Which of the following could not be the total value of the four coins, in cents?
1515
2525
3535
4545
5555
Answer: A
Concepts:moneydivisibilitybounding to limit cases
Small hint:
A total that is a multiple of 55 forces the number of pennies to be a multiple of 55
Big hint:
With no pennies, four coins are worth at least 4⋅5=204 \cdot 5 = 20 cents
Solution:
To get a multiple of 55 cents, the number of pennies must be a multiple of 5.5. With only four coins, that means using no pennies, but then the four coins are each worth at least 55 cents, for a total of at least 2020 cents.
So 1515 cents cannot be made. The others can: 25=10+3(5),25 = 10 + 3(5), 35=3(10)+5,35 = 3(10) + 5, 45=25+10+2(5),45 = 25 + 10 + 2(5), and 55=25+3(10).55 = 25 + 3(10).
Thus, the correct answer is A.
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