2005 AMC 10A Problem 9

Attempt Problem 9 of the 2005 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

Three tiles are marked X and two other tiles are marked O. The five tiles are randomly arranged in a row. What is the probability that the arrangement reads XOXOX?
112\dfrac{1}{12}
110\dfrac{1}{10}
16\dfrac{1}{6}
14\dfrac{1}{4}
13\dfrac{1}{3}
Answer: B
Concepts:basic probabilitycombinations
Small hint:
Count the distinct arrangements of three X’s and two O’s in a row
Big hint:
The two O’s occupy (52)\binom{5}{2} equally likely position sets, and only one of them gives XOXOX
Solution:
The three X positions can be any of (53)=10\binom{5}{3} = 10 equally likely choices, and exactly one of them produces XOXOX. So the probability is 110.\dfrac{1}{10}.
Thus, the correct answer is B.
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