2003 AMC 10B Problem 2

Attempt Problem 2 of the 2003 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

Al gets the disease algebritis and must take one green pill and one pink pill each day for two weeks. A green pill costs $1\$1 more than a pink pill, and Al’s pills cost a total of $546\$546 for the two weeks. How much does one green pill cost?
$7\$7
$14\$14
$19\$19
$20\$20
$39\$39
Answer: D
Concepts:moneylinear equation
Small hint:
Two weeks is 1414 days, so find the cost of one day’s pills
Big hint:
If a pink pill costs p,p, then the green pill costs p+1p+1 and p+(p+1)=39p+(p+1)=39
Solution:
Each day’s pills cost 546÷14=39546 \div 14 = 39 dollars. If xx is the cost of a green pill, then the pink pill costs x−1,x-1, so x+(x−1)=39.x+(x-1)=39. Solving gives x=20.x=20.
Thus, the correct answer is D.
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