2001 AMC 10 Problem 9

Attempt Problem 9 of the 2001 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

The state income tax where Kristin lives is levied at the rate of p%p\% of the first $28000\$28000 of annual income plus (p+2)%(p+2)\% of any amount above $28000.\$28000. Kristin noticed that the state income tax she paid amounted to (p+0.25)%(p+0.25)\% of her annual income. What was her annual income?
$28000\$28000
$32000\$32000
$35000\$35000
$42000\$42000
$56000\$56000
Answer: B
Concepts:percentagelinear equation
Small hint:
Let her income be x>28000x\gt28000 and write the tax two different ways
Big hint:
p100(28000)\dfrac{p}{100}(28000) +p+2100(x−28000)+\dfrac{p+2}{100}(x-28000) =p+0.25100x=\dfrac{p+0.25}{100}x
Solution:
Let her income be x≥28000.x\ge28000. Then
p100(28000)+p+2100(x−28000)=p+0.25100x. \begin{aligned} &\tfrac{p}{100}(28000) \\ &\quad {}+\tfrac{p+2}{100}(x-28000) \\ &\quad =\tfrac{p+0.25}{100}x. \end{aligned}
Multiplying by 100100 and expanding, all the pp terms cancel, leaving 2x−56000=0.25x.2x-56000=0.25x. So 1.75x=560001.75x=56000 and x=32000.x=32000.
Thus, the correct answer is B.
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