2000 AMC 10 Problem 1

Attempt Problem 1 of the 2000 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

In the year 2001,2001, the United States will host the International Mathematical Olympiad. Let I,I, M,M, and OO be distinct positive integers such that the product I⋅M⋅O=2001.I \cdot M \cdot O = 2001. What is the largest possible value of the sum I+M+O?I + M + O?
2323
5555
9999
111111
671671
Answer: E
Concepts:prime factorizationoptimization
Small hint:
Factor 20012001 into primes
Big hint:
To make the sum large, keep one factor as small as possible so another can be as large as possible
Solution:
Factoring gives 2001=3⋅23⋅29.2001 = 3 \cdot 23 \cdot 29.
If one factor is 1,1, the possible pairs for the other two factors are (3,667),(3,667), (23,87),(23,87), and (29,69).(29,69). Their corresponding sums with 11 are 671,671, 111,111, and 99.99. (The pair (1,2001)(1,2001) would repeat the factor 1.1.)
If no factor is 1,1, all three prime factors must be split among the three integers, giving only 3,23,293,23,29 and a much smaller sum. Therefore, the largest possible sum is 1+3+667=671.1 + 3 + 667 = 671.
Thus, the correct answer is E.
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