1992 AIME Problem 12

Attempt Problem 12 of the 1992 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AIME solutions, or check the answer key.

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12.

In a game of Chomp, two players alternately take bites from a 55-by-77 grid of unit squares. To take a bite, a player chooses one of the remaining squares, then removes (“eats”) all squares in the quadrant defined by the left edge (extended upward) and the lower edge (extended rightward) of the chosen square. For example, the bite determined by the shaded square in the diagram would remove the shaded square and the four squares marked by ×.\times. (The squares with two or more dotted edges have been removed from the original board in previous moves.)

The object of the game is to make one’s opponent take the last bite. The diagram shows one of the many subsets of the set of 3535 unit squares that can occur during the game of Chomp. How many different subsets are there in all? Include the full board and empty board in your count.

Answer: 792
Concepts:lattice pathscombinationssubsets
Difficulty rating: 2320
Small Hint:

A reachable set is determined by nonincreasing column heights between 00 and 55

Big Hint:

Encode the boundary of such a set as a lattice path with 55 vertical and 77 horizontal steps

Solution:

After any sequence of bites, the remaining squares form a lower-left order ideal: the seven column heights are nonincreasing integers between 00 and 5.5. Conversely, every such boundary can be produced and corresponds to a lattice path across a 55-by-77 rectangle. Each path consists of 55 vertical and 77 horizontal steps, so the number of states, including full and empty, is (125)=792.\binom{12}{5}=792.

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