1988 AIME Problem 14

Attempt Problem 14 of the 1988 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AIME solutions, or check the answer key.

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14.

Let CC be the graph of xy=1,xy=1, and denote by CC^* the reflection of CC in the line y=2x.y=2x. Let the equation of CC^* be written in the form

12x2+bxy+cy2+d=0.12x^2+bxy+cy^2+d=0.

Find the product bc.bc.

Answer: 84
Concepts:reflection (geometry)transformationhyperbola
Difficulty rating: 2170
Small Hint:

Find the reflection matrix for the line spanned by (1,2)(1,2)

Big Hint:

Because reflection is its own inverse, substitute the reflected coordinates into uv=1uv=1

Solution:

Reflection in the line spanned by (1,2)(1,2) has matrix 15(3443).\frac15\begin{pmatrix}-3&4\\4&3\end{pmatrix}. Thus a point (x,y)(x,y) on CC^* came from u=3x+4y5u=\frac{-3x+4y}{5} and v=4x+3y5v=\frac{4x+3y}{5} on C.C. Substituting uv=1uv=1 gives 12x2+7xy+12y225=0,-12x^2+7xy+12y^2-25=0, or 12x27xy12y2+25=0.12x^2-7xy-12y^2+25=0. Hence b=7,b=-7, c=12,c=-12, and bc=84.bc=84.

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