2012 AMC 8 第 13 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

13.

Jamar 在学校书店买了一些铅笔,每支铅笔价格超过一美分,共支付 $1.43\$1.43。Sharona 买了同样的铅笔,共支付 $1.87\$1.87。Sharona 比 Jamar 多买了多少支铅笔?

Jamar bought some pencils costing more than a penny each at the school bookstore and paid $1.43.\$1.43. Sharona bought some of the same pencils and paid $1.87.\$1.87. How many more pencils did Sharona buy than Jamar?

22

33

44

55

66

答案:C
知识点:最大公约数整除性
难度评级:1310
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文字解答:

设每支铅笔价格为 cc 美分。 则 cc 同时整除 143143187187,且 c>1c\gt1

因为 143=1113143=11\cdot13,且 187=1117187=11\cdot17,最大公因数是 1111。 所以每支铅笔 1111 美分。

Sharona 多付了 187143=44187-143=44 美分,所以她多买了 44/11=444/11=4 支铅笔。 所以正确答案是 C

Let cc be the price of one pencil in cents. Then cc divides both 143143 and 187187, and c>1c\gt1.

Since 143=1113143=11\cdot13 and 187=1117187=11\cdot17, the greatest common divisor is 1111. Thus each pencil costs 1111 cents.

Sharona paid 187143=44187-143=44 cents more, so she bought 44/11=444/11=4 more pencils. Thus, the answer is C .

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