2012 AMC 8 Problem 14

Below is the video solution and professionally curated solution for Problem 14 of the 2012 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 8 solutions, or check the answer key.

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Concepts:combinationstriangular number

Difficulty rating: 1100

14.

In the BIG N, a middle school football conference, each team plays every other team exactly once. If a total of 2121 conference games were played during the 20122012 season, how many teams were members of the BIG N conference?

6 6

7 7

8 8

9 9

10 10

Video solution:
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Written solution:

Each of the NN teams plays N1N-1 games. However, 22 teams play each game, so multiplying NN and N1N-1 would be twice the number of games. Therefore, we know N(N1)=42.N(N-1) = 42. This leads to N2N+0.25=42.25N^2 -N +0.25 = 42.25 which implies (N0.5)2=6.52.(N-0.5)^2 = 6.5^2. In turn, this suggests: N0.5=6.5N-0.5 = 6.5N=7 N = 7

Thus, the answer is B .

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