2010 AMC 8 第 11 题

先试着解答 2010 AMC 8 第 11 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2010 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

11.

一棵树的树顶比另一棵树的树顶高 1616 英尺。两棵树的高度之比为 3:43:4。较高的树高多少英尺?
The top of one tree is 1616 feet higher than the top of another tree. The heights of the two trees are in the ratio 3:4.3:4. In feet, how tall is the taller tree?
 48\ 48
 64\ 64
 80\ 80
 96\ 96
 112\ 112
答案:B
知识点:比与比例一次方程
小提示:
较高的树包含四份这样的相等部分
The taller tree has four of those equal parts.
大提示:
比值 3:43:4 表示高度差是一份
The ratio 3:43:4 means the height difference is one ratio part.
解答:
设较高和较矮的树高分别为 bb、ss。则 b=s+16b= s+16,且 s=0.75bs = 0.75b。代入得 b=0.75b+16  ⟹  0.25b=16b = 0.75b + 16 \implies 0.25b = 16   ⟹  b=64。\implies b = 64\text{。}
所以正确答案是 B。
Let b,b, ss be the heights of bigger and smaller trees respectively. Then, b=s+16b= s+16 and s=0.75b. s = 0.75b. If we substitute, we get b=0.75b+16  ⟹  0.25b=16b = 0.75b + 16 \implies 0.25b = 16   ⟹  b=64.\implies b = 64.
Thus, the answer is B .
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