2008 AMC 8 第 11 题

先试着解答 2008 AMC 8 第 11 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2008 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

11.

林肯中学八年级的 3939 名学生中,每人养一只狗、一只猫,或狗和猫都养。有二十名学生养狗,2626 名学生养猫。有多少名学生狗和猫都养?
Each of the 3939 students in the eighth grade at Lincoln Middle School has one dog or one cat or both a dog and a cat. Twenty students have a dog and 2626 students have a cat. How many students have both a dog and a cat?
 7\ 7
 13\ 13
 19\ 19
 39\ 39
 46\ 46
答案:A
知识点:容斥原理
小提示:
把养狗人数和养猫人数相加时,同时养两种宠物的学生被数了两次
Adding dog owners and cat owners counts students with both pets twice.
大提示:
用容斥原理,总人数就是并集大小
Use inclusion-exclusion with the total number of students as the union.
解答:
同时养两种动物的人数等于养猫人数加养狗人数,再减去至少养一种动物的人数。
因此同时养两种动物的人数为 20+26−39=7。20+26-39 = 7\text{。}
所以正确答案是 A。
The number of people that have both animals is equal to the number of people that own a cat plus the number of people that own a dog minus the number of people that own either.
Therefore, the number of people who own both is 20+26−39=7.20+26-39 = 7.
Thus, the answer is A .
LIVE by Po-Shen Loh
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