2006 AMC 10A 第 17 题

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17.

在矩形 ADEHADEH 中,点 BBCC 三等分 AD\overline{AD},点 GGFF 三等分 HE\overline{HE}。此外,AH=AC=2AH = AC = 2。图中四边形 WXYZWXYZ 的面积是多少?

In rectangle ADEH,ADEH, points BB and CC trisect AD,\overline{AD}, and points GG and FF trisect HE.\overline{HE}. In addition, AH=AC=2.AH = AC = 2. What is the area of quadrilateral WXYZWXYZ shown in the figure?

12\dfrac{1}{2}

22\dfrac{\sqrt{2}}{2}

32\dfrac{\sqrt{3}}{2}

223\dfrac{2\sqrt{2}}{3}

233\dfrac{2\sqrt{3}}{3}

答案:A
知识点:坐标几何面积正方形(几何)
难度评级:1540
解答:

A=(0,0)A = (0, 0)D=(3,0)D = (3, 0)H=(0,2)H = (0, 2),则 B=(1,0)B = (1, 0)C=(2,0)C = (2, 0)G=(1,2)G = (1, 2)F=(2,2)F = (2, 2)E=(3,2)E = (3, 2)

图中线段交于 W=(1.5,1.5)W = (1.5, 1.5)X=(1,1)X = (1, 1)Y=(1.5,0.5)Y = (1.5, 0.5)Z=(2,1)Z = (2, 1)。这些点形成一个正方形,其垂直对角线 WYWYXZXZ 的长度都为 11

面积为 1211=12\frac12 \cdot 1 \cdot 1 = \frac12

所以正确答案是 A

Set A=(0,0),A = (0, 0), D=(3,0),D = (3, 0), H=(0,2),H = (0, 2), so B=(1,0),B = (1, 0), C=(2,0),C = (2, 0), G=(1,2),G = (1, 2), F=(2,2),F = (2, 2), and E=(3,2).E = (3, 2).

The drawn segments meet at W=(1.5,1.5),W = (1.5, 1.5), X=(1,1),X = (1, 1), Y=(1.5,0.5),Y = (1.5, 0.5), and Z=(2,1).Z = (2, 1). These form a square whose perpendicular diagonals WYWY and XZXZ each have length 1.1.

Its area is 1211=12.\frac12 \cdot 1 \cdot 1 = \frac12.

Thus, the correct answer is A.

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