2025 AMC 8 Problem 7
Attempt Problem 7 of the 2025 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
7.
On the most recent exam in Prof. Xochi’s class,
• students earned a score of at least
• students earned a score of at least
• students earned a score of at least and
• students earned a score of at least
How many students earned a score of at least and less than
Answer: D
Small hint:
The score groups are nested
Big hint:
Subtract the students with scores at least from those at least
Video solution:
Click to load, then click again to play
Written solution:
Notice that the numbers of students in each category keep increasing, which makes sense because the categories are getting broader.
We want to include all of the students who earned a score of at least but exclude all of the students who earned a score of at least So, the answer is which is choice D.
Problem 7 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
- 1995 AMC 8
- 1996 AMC 8
- 1997 AMC 8
- 1998 AMC 8
- 1999 AMC 8
- 2000 AMC 8
- 2001 AMC 8
- 2002 AMC 8
- 2003 AMC 8
- 2004 AMC 8
- 2005 AMC 8
- 2006 AMC 8
- 2007 AMC 8
- 2008 AMC 8
- 2009 AMC 8
- 2010 AMC 8
- 2011 AMC 8
- 2012 AMC 8
- 2013 AMC 8
- 2014 AMC 8
- 2015 AMC 8
- 2016 AMC 8
- 2017 AMC 8
- 2018 AMC 8
- 2019 AMC 8
- 2020 AMC 8
- 2022 AMC 8
- 2023 AMC 8
- 2024 AMC 8
- 2026 AMC 8